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- Subject
- Periodic Classificationchemistry-mcqs › periodic-classification
- Published
- 18 Mar 2019
- Last updated
- 28 May 2026
Explanation
Iodine is solid at room temperature primarily because of its high polarizability, which leads to strong London dispersion forces between molecules. It does not have strong covalent bonds between molecules, nor significant dipole moments or hydrogen bonding, which explains why options A, B, and D are incorrect.
More Periodic Classification MCQs
Practice related questions from the same subject.
- 1.Which of the following statements about metals is false?
- 2.Considering atomic sizes, which of the following comparisons is accurate?
- 3.What term is used for halides where halogen atoms serve as bridges connecting two atoms of another element?
- 4.What does the oxidation state of an atom indicate?
- 5.How does the metallic character of alkali metals change as you move down the group?
- 6.What is the nature of the energy change when a second electron is added to a singly charged negative ion?
- 7.Which factors influence the ionization energy of an atom?
- 8.What compound is produced when deuterium combines with oxygen?
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