Two copper wires of the same length have different cross-sectional areas. If the area of one wire is four times larger than the other, and the wire with the smaller area has a resistance of 40 ohms, what is the resistance of the thicker wire?

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Published
28 Jun 2018
Last updated
28 May 2026

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Explanation

Since both copper wires are of equal length, resistance is inversely proportional to the cross-sectional area. The thicker wire has four times the area, so its resistance is one-fourth that of the thinner wire. Therefore, the resistance of the thicker wire is 40 ohms ÷ 4 = 10 ohms.

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