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- Subject
- Electromagnetic Inductionelectrical-engineering-mcqs › electromagnetic-induction
- Published
- 16 Dec 2018
- Last updated
- 28 May 2026
Explanation
The induced e.m.f. (E) in a conductor moving perpendicular to a magnetic field is given by E = B × l × v, where B is the magnetic flux density (1 T), l is the length of the conductor (2 m), and v is the velocity (12.5 m/s). Calculating: 1 × 2 × 12.5 = 25 volts, which corresponds to option C.
More Electromagnetic Induction MCQs
Practice related questions from the same subject.
- 1.Can the left-hand generator rule be used to identify the polarity of an induced voltage?
- 2.Will changing the direction of either the magnetic field or the current reverse the force acting on a conductor?
- 3.Is the self-inductance of a coil defined as the electromotive force (in volts) induced when the current changes at a rate of one Weber-turn per second?
- 4.Which component in a circuit resists changes in the current flow?
- 5.A coil is wrapped around an iron core carrying a current I. Which factor does NOT influence the self-induced voltage in the coil?
- 6.What is the effect of a fracture in the magnetic core of an inductor?
- 7.The coupling coefficient between two air-core inductors is determined by which of the following?
- 8.If the current in a coil increases from 8 A to 12 A within one second and induces an emf of 20 volts, what is the inductance of the coil?
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