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- Subject
- Electrostaticselectrical-engineering-mcqs › electrostatics
- Published
- 15 Dec 2018
- Last updated
- 28 May 2026
Explanation
The energy stored in a capacitor is given by the formula E = 1/2 C V². Here, C = 1 F and V = 4 V, so E = 0.5 × 1 × (4)² = 8 joules.
More Electrostatics MCQs
Practice related questions from the same subject.
- 1.Identify the statement that is incorrect regarding electric charges:
- 2.Which of the following statements about electric lines of force is accurate?
- 3.Which type of capacitor is most likely to overheat and explode if connected incorrectly in a circuit?
- 4.Which type of capacitor is identified by having polarity markings?
- 5.What is the amount of power lost in an ideal capacitor?
- 6.What happens to the voltage across the plates of a parallel plate capacitor when a dielectric material is inserted between them?
- 7.What components make up a capacitor?
- 8.In what form is a paper capacitor commonly manufactured?
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