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- Subject
- OP-AMP Circuitselectrical-engineering-mcqs › op-amp-circuits
- Published
- 17 Dec 2018
- Last updated
- 28 May 2026
Explanation
Given the differential gain (Ad) is 20,000 and CMRR is 80 dB, the common mode gain (Ac) can be found using the relation CMRR (dB) = 20 log(Ad/Ac). Converting 80 dB to a ratio gives 10,000. Therefore, Ac = Ad / 10,000 = 20,000 / 10,000 = 2.
More OP-AMP Circuits MCQs
Practice related questions from the same subject.
- 1.An operational amplifier has a slew rate of 5 V/μs. What is the maximum peak output voltage of a sine wave at a frequency of 1 MHz that the amplifier can produce without distortion?
- 2.Given a 741 operational amplifier with a gain-bandwidth product of 1 MHz, what is the -3 dB bandwidth of a non-inverting amplifier configured with this op-amp and a voltage gain of 20 dB?
- 3.Why is a differential amplifier consistently employed at the input stage of operational amplifiers?
- 4.Consider the ideal op-amp circuit shown in the figure. If the input voltage Vi is a triangular waveform, what will be the shape of the output voltage V0?
- 5.Which type of amplifier is commonly utilized in a digital-to-analog converter?
- 6.What type of output does an op-amp integrator produce when a step input is applied?
- 7.Which statement accurately describes an ideal operational amplifier?
- 8.If a differential amplifier has a differential voltage gain of 48 dB and a common-mode voltage gain of 2 dB, what is its common-mode rejection ratio (CMRR)?
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