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- Subject
- Parallel Circuitselectrical-engineering-mcqs › parallel-circuits
- Published
- 19 Dec 2018
- Last updated
- 28 May 2026
Explanation
Initially, the total resistance for five 100 Ω resistors in parallel is 20 Ω (since 1/R_total = 5/100). Removing one resistor leaves four resistors in parallel, so the new total resistance is 100/4 = 25 Ω.
More Parallel Circuits MCQs
Practice related questions from the same subject.
- 1.A total current of 800 mA flows into a set of four resistors connected in parallel. If the currents through three of these resistors are 40 mA, 70 mA, and 200 mA respectively, what is the current passing through the fourth resistor?
- 2.What happens to the overall resistance in a parallel circuit when one resistor is taken out?
- 3.In a parallel circuit with three branches, the currents flowing through each branch are 200 mA, 340 mA, and 700 mA respectively, all measured in the same direction. What is the total current entering the junction of these branches?
- 4.Four resistors are connected in parallel. The current passing through the resistor with resistance R is 15 mA. If the other three resistors have values 2R, 3R, and 4R respectively, what is the total current flowing through the entire circuit?
- 5.Six resistors are connected in parallel, with the two smallest resistors each having a resistance of 1.2 kΩ. What can be said about the total equivalent resistance?
- 6.Six resistors are connected in parallel, with the two smallest resistors each having a resistance of 1.2 kΩ. What can be said about the total resistance of the combination?
- 7.Three resistors of 220Ω, 470Ω, and 560Ω are connected in parallel to a voltage source. Which resistor carries the smallest current?
- 8.In a parallel circuit with three branches, the currents through R1, R2, and R3 are 12 mA, 15 mA, and 25 mA respectively. If the total current measured is only 27 mA, what can be concluded?
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