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- Subject
- Electrical Engineering Mcqselectrical-engineering-mcqs
- Published
- 22 Mar 2019
- Last updated
- 28 May 2026
Explanation
The potential V on the surface of a charged hollow sphere is given by V = kQ / R, where k is Coulomb's constant (9 × 10⁹ Nm²/C²), Q is the charge, and R is the radius in meters. Given diameter = 8 cm, so radius R = 0.04 m. Substituting the values, V = (9 × 10⁹)(4 × 10⁻⁸) / 0.04 = 9000 volts.
More Electrical Engineering Mcqs
Practice related questions from the same subject.
- 1.For which voltage levels is solid grounding typically applied?
- 2.What is the primary factor to focus on when developing an effective design?
- 3.How many elementary charges (e) are equivalent to one Coulomb of charge?
- 4.Under which condition is a turbine automatically shut down?
- 5.Which device is utilized to measure the electrical power in a circuit?
- 6.What happens to the force between two point charges if the distance separating them is reduced to half?
- 7.Two electric charges, one with 100 C and the other with 16.9 C, are separated by a distance of 13 cm. What is the magnitude of the electric force between them?
- 8.If two charges are separated by a fixed distance and the magnitude of each charge is doubled, how will the electrostatic force between them change?
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