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- Problems on L.C.M and H.C.Fmathematics-mcqs › problems-on-l-c-m-and-h-c-f
- Published
- 12 Jul 2019
- Last updated
- 28 May 2026
Explanation
To find the smallest four-digit number divisible by 4, 6, 8, and 10, first determine the least common multiple (LCM) of these numbers. The LCM is 120. The smallest four-digit number is 1000. Dividing 1000 by 120 gives a quotient of 8 with a remainder of 40. Adding (120 - 40) = 80 to 1000 results in 1080, which is the smallest four-digit number divisible by all given divisors.
More Problems on L.C.M and H.C.F MCQs
Practice related questions from the same subject.
- 1.What is the smallest perfect square that is divisible by 10, 12, 15, and 18?
- 2.Three men begin simultaneously to run along a circular track that measures 11 kilometers in circumference. Their speeds are 4 km/h, 5 km/h, and 8 km/h respectively. After how many hours will they all meet again at the starting point together?
- 3.What is the smallest number that leaves remainders of 1, 2, 3, 4, and 5 when divided by 6, 7, 8, 9, and 10 respectively, and is also exactly divisible by 19?
- 4.What is the smallest multiple of 13 that, when divided by 6, 8, and 12, leaves remainders of 5, 7, and 11 respectively?
- 5.What is the smallest number that leaves remainders of 1, 2, 3, 4, and 5 when divided by 2, 3, 4, 5, and 6 respectively, and is exactly divisible by 7?
- 6.A pile of stones can be evenly divided into groups of 21 without any remainder. However, when the stones are grouped into sets of 16, 20, 25, or 45, there are always 3 stones left over. What is the smallest possible number of stones in the pile?
- 7.What is the largest four-digit number that leaves remainders of 4, 9, 15, and 22 when divided by 10, 15, 21, and 28 respectively?
- 8.What is the smallest number that leaves a remainder of 25 when divided by 35, a remainder of 15 when divided by 25, and a remainder of 5 when divided by 15?
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