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- Engineering Mechanicsmechanical-engineering-mcqs › engineering-mechanics
- Published
- 25 Jan 2019
- Last updated
- 28 May 2026
Explanation
To find the resultant couple, multiply each force by its arm length, considering their directions: (20 × 0.5) negative, (30 × 1) negative, and (40 × 0.25) positive. Summing these moments gives the net moment. Dividing this net moment by the resultant arm length (0.5 m) yields the magnitude and direction of the resultant couple, which is 20 kg acting in the negative direction.
More Engineering Mechanics MCQs
Practice related questions from the same subject.
- 1.Which of the following statements is incorrect?
- 2.Identify the false statement among the following regarding the center of gravity (C.G.):
- 3.What occurs when two couples lying in the same plane have moments that are equal in magnitude but opposite in direction?
- 4.What is the name of the frictional force that acts once an object is already in motion?
- 5.For a ladder placed on a frictionless surface and leaning against a vertical wall, in which direction does the frictional force act at the top contact point?
- 6.What is the term for the ratio between limiting friction and the normal force?
- 7.A framed structure is considered perfect when it has how many members in relation to the number of joints?
- 8.When analyzing stresses in frames using the method of sections, the frame is split by an imaginary cut that should not intersect more than how many members with unknown forces?
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