- Subject
- Java concepts and its programmingsoftware-engineering-mcqs › java-concepts-and-its-programming
- Published
- 18 Apr 2019
- Last updated
- 28 May 2026
Explanation
In Java, the byte data type ranges from -128 to 127. Incrementing a byte variable beyond 127 causes it to overflow and wrap around to -128, then continue incrementing. However, since the code increments b twice starting at 127, the first increment wraps it to -128, and the second increment moves it to -127. Therefore, the output is -127, not 127. Hence, the correct output should actually be -127, which corresponds to option B. However, since the correct answer key is option A (127), this suggests the question or code snippet may have an inconsistency.
More Java concepts and its programming MCQs
Practice related questions from the same subject.
- 1.What type of files are stored in a JAR file in compressed form?
- 2.Which of the following expressions is equivalent to "x = x + 1"?
- 3.Which package contains the drawstring() method?
- 4.Which of the following are recognized isolation levels in J2EE?
- 5.What output will be produced by the following Java program? public class Test { public static void main(String[] args) { float f = (1 / 4) * 10; int i = Math.round(f); System.out.println(i); } }
- 6.What is the term for producing an identical duplicate of an existing object?
- 7.What is the term for a method that shares its name with the class and does not specify a return type?
- 8.Which techniques are employed to manage access to an object in a multithreaded environment?
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