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- Subject
- Permutations and Combinationsmathematics-mcqs › permutations-and-combinations
- Published
- 24 Jul 2019
- Last updated
- 28 May 2026
Explanation
Each ring has 6 distinct letters, so the total number of possible combinations is 6 × 6 × 6 = 216. Since only one combination unlocks the lock, the greatest number of unsuccessful tries is 216 minus 1, which equals 215.
More Permutations and Combinations MCQs
Practice related questions from the same subject.
- 1.Three flags, each of a distinct color, are used in a military drill to create different signaling codes by waving: I. A single flag of any color II. Any two flags in a specific order III. All three flags in various sequences What is the maximum number of unique codes that can be formed?
- 2.A question paper contains five problems, each with three internal options. In how many different ways can a candidate attempt at least one problem by choosing one option per problem?
- 3.There are 20 male students and 25 female students in a class. How many different pairs consisting of one boy and one girl can be formed?
- 4.How many different ways can you choose three consonants and two vowels from the letters in the word "TRIANGLE"?
- 5.A container holds 9 yellow balls, 3 white balls, and 4 red balls. How many different ways can you select two balls from this collection?
- 6.Using the digits {1, 2, 3, 5, 7, 9}, how many distinct four-digit even numbers can be created?
- 7.Using the digits {1, 3, 4, 5, 7, 9} without repeating any digit, how many unique four-digit numbers can be created?
- 8.In how many different ways can six boys and six girls be arranged in a single row for a photograph such that no two girls are seated next to each other?
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