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- Subject
- Permutations and Combinationsmathematics-mcqs › permutations-and-combinations
- Published
- 24 Jul 2019
- Last updated
- 28 May 2026
Explanation
First, arrange the six boys in 6! different ways. This creates seven potential spots around them where the girls can be placed without sitting together. Since there are six girls and seven available positions, the girls can be arranged in 7P6 ways. Therefore, the total number of arrangements is 6! × 7P6, which equals (6!)².
More Permutations and Combinations MCQs
Practice related questions from the same subject.
- 1.Three flags, each of a distinct color, are used in a military drill to create different signaling codes by waving: I. A single flag of any color II. Any two flags in a specific order III. All three flags in various sequences What is the maximum number of unique codes that can be formed?
- 2.A question paper contains five problems, each with three internal options. In how many different ways can a candidate attempt at least one problem by choosing one option per problem?
- 3.There are 20 male students and 25 female students in a class. How many different pairs consisting of one boy and one girl can be formed?
- 4.How many different ways can you choose three consonants and two vowels from the letters in the word "TRIANGLE"?
- 5.A container holds 9 yellow balls, 3 white balls, and 4 red balls. How many different ways can you select two balls from this collection?
- 6.Using the digits {1, 2, 3, 5, 7, 9}, how many distinct four-digit even numbers can be created?
- 7.Using the digits {1, 3, 4, 5, 7, 9} without repeating any digit, how many unique four-digit numbers can be created?
- 8.A lock features three rotating rings, each displaying six unique letters. What is the maximum number of failed attempts possible before the lock opens?
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