Given the quadratic equations I. a² - 13a + 42 = 0 and II. b² - 15b + 56 = 0, determine the correct relationship between the values of a and b obtained by solving these equations.

Quadratic Equations MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

PPSCFPSCNTSPakistan govt jobs
Subject
Quadratic Equationsmathematics-mcqs › quadratic-equations
Published
11 Jul 2019
Last updated
28 May 2026

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Explanation

Solving the first equation: a² - 13a + 42 = 0 factors as (a - 6)(a - 7) = 0, giving a = 6 or 7. Solving the second equation: b² - 15b + 56 = 0 factors as (b - 7)(b - 8) = 0, giving b = 7 or 8. Comparing the values, the maximum value of a is 7 and the minimum value of b is 7, so a is always less than or equal to b.

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