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What are the solutions to the quadratic equation x² + x - 42 = 0?

Quadratic Equations MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

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Subject
Quadratic Equationsmathematics-mcqs › quadratic-equations
Published
11 Jul 2019
Last updated
28 May 2026

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Explanation

To solve x² + x - 42 = 0, factor the equation as (x + 7)(x - 6) = 0. Setting each factor equal to zero gives the roots x = -7 and x = 6.

More Quadratic Equations MCQs

Practice related questions from the same subject.

  1. 1.What are the solutions to the quadratic equation 3x² - 7x - 6 = 0?
  2. 2.What are the solutions of the quadratic equation 2x² + 5x + 2 = 0?
  3. 3.Given the quadratic equations I. a² - 13a + 42 = 0 and II. b² - 15b + 56 = 0, determine the correct relationship between the values of a and b obtained by solving these equations.
  4. 4.Given the equations: (i) a³ − 988 = 343 and (ii) b² − 72 = 49, determine the correct relationship between the values of a and b.
  5. 5.Given the quadratic equations I. 9a² + 18a + 5 = 0 and II. 2b² + 13b + 20 = 0, determine the correct relationship between the values of a and b after solving both equations.
  6. 6.Given the quadratic equations I. x² + 11x + 30 = 0 and II. y² + 15y + 56 = 0, what is the correct relationship between the values of x and y after solving both equations?
  7. 7.Given the quadratic equations I. x² + 3x - 18 = 0 and II. y² + y - 30 = 0, what can be concluded about the relationship between x and y after solving both?
  8. 8.Given the equations I. x² + 9x + 20 = 0 and II. y² + 5y + 6 = 0, determine the relationship between the values of x and y after solving both equations.
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