Given the equations I. x² - x - 42 = 0 and II. y² - 17y + 72 = 0, determine the relationship between the values of x and y obtained by solving both equations.

Quadratic Equations MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

PPSCFPSCNTSPakistan govt jobs
Subject
Quadratic Equationsmathematics-mcqs › quadratic-equations
Published
11 Jul 2019
Last updated
28 May 2026

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Explanation

Solving equation I: x² - x - 42 = 0 factors as (x - 7)(x + 6) = 0, giving x = 7 or x = -6. Solving equation II: y² - 17y + 72 = 0 factors as (y - 8)(y - 9) = 0, yielding y = 8 or y = 9. Comparing the values, the possible x values are 7 and -6, while y values are 8 and 9. Since both 7 < 8 and -6 < 9, the relationship is x < y.

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